Category Archives: Helpful Hints

Formula Sheet for Midterm 2 (along with some Midterm 2 – related information)

The formula sheet for Midterm Exam 2 is now available at http://fin4335.garven.com/fall2019/formulas_part2.pdf. This document will be appended to the back of the Midterm 2 exam booklet that y’all will get to see for the first time on Tuesday.  In my opinion, the two most important Midterm 2 – related documents are the formula sheet and the Finance 4335 course synopsis for Midterm Exam 2.

Here’s some further information about Midterm 2 (to be given in class on Tuesday, November 5):

  • Midterm 2 consists of two sections. Section 1 consists of six multiple choice and two short answer questions worth 4 points each, whereas Section 2 consists of three problems worth 32 points each.
  • Students are required to either complete Section 1 questions and two out of three Section 2 problems, or to ignore Section 1 and complete all three Section 2 problems. For students who complete all of Sections 1 and 2, I will count the three highest scoring questions and/or problems toward the exam grade.
  • The maximum number of points possible on this exam’s questions and problems totals 96, and I will add an additional 4 points on your exam if you legibly write your name on the cover page in the space provided. Thus, the maximum number of points possible on this exam is 100 points.

Let me know whether you have any Midterm 2 – related questions or concerns.  If you need to contact me tomorrow, call or text during business hours to 254-307-1317, or email me at James_Garven@baylor.edu.

Easy access to solutions for problem sets, class problems, and the Spring 2019 midterm 2

As I mentioned during our class meeting yesterday, http://risk.garven.com/category/problem-set-solutions/ opens a webpage that features a chronologically ordered (from most to least recent) listing of links for 3 assigned problem sets (problem sets 5-7) and 6 class problems given in Finance 4335 since Midterm 1.

I have also posted the Spring 2019 Midterm 2 exam booklet and solutions on the Sample Exams page of the Finance 4335 course website.  Once I have completed writing the Fall 2019 Midterm 2 exam, I will post this exam’s formula sheet on the Finance 4335 Formula Sheets page.

Restrictions on Use: Section III.C.16 of Baylor’s Honor Code Policy and Procedures stipulates that using, uploading, or downloading any online resource derived from material pertaining to a Baylor course without the written permission of the professor constitutes an act of academic dishonesty.  Since Professor Garven gives no such permission for Finance 4335 course content, this means that the use and redistribution of Finance 4335-related documents involving any source other than Professor Garven are expressly forbidden.  For more information on the use restrictions of Finance 4335 course content, see http://bit.ly/4335honorcode.  

Problem set 7 helpful hint

Here is a helpful hint for parts 1D and 2C of problem set 7. As we showed last week in class, the weights for the minimum variance two-asset portfolio can be found by applying the following ratio in order to determine w1; upon calculating w1, then w2 = 1 – w1. (source: p. 7 of http://fin4335.garven.com/fall2019/lecture12.pdf):

{w_1} = \displaystyle\frac{{\sigma _2^2 - {\sigma _{12}}}}{{\sigma _1^2 + \sigma _2^2 - 2{\sigma _{12}}}}.

Furthermore, in cases where correlation is equal to either -1 or 1, the weighting scheme shown above guarantees that the minimum variance combination is riskless. Therefore, if the expected return on a riskless two-asset portfolio is either greater or less than the expected return on a riskless asset, there’d be a riskless arbitrage opportunity. In such cases, one would want to buy the higher yielding investment and short the lower yielding investment. Although no risk is involved, we assume (here as well as throughout the course) that marginal utility of wealth is positive for all decision-makers.

Problem Set 6 Hints and Spreadsheet

Problem Set 6 is due at the beginning of class on Tuesday, October 22.

In question 1, part C of Problem Set 6, I ask you to “Find the maximum price which the insurer can charge for the coinsurance contract such that profit can still be earned while at the same time providing the typical Florida homeowner with higher expected utility from insuring and retrofitting. How much profit will the insurer earn on a per policy basis?” Here are some hints which you’ll hopefully find helpful.

For starters, keep in mind that in part A, insurance is compulsory (i.e., required by law), whereas, in parts B and C, insurance is not compulsory. In part B of question 1, you are asked to show that the homeowner retrofits while choosing not to purchase insurance. However, in part C, the homeowner might retrofit and purchase coverage if the coinsurance contract is priced more affordably. Therefore, the insurer’s problem is to figure out how much it must reduce the price of the coinsurance contract so that the typical Florida homeowner will have higher expected utility from insuring and retrofitting compared with the part B’s alternative of retrofitting only. It turns out that this is a fairly easy problem to solve using Solver. If you download the spreadsheet located at http://fin4335.garven.com/fall2019/ps6.xls, you can find the price at which the consumer would be indifferent between buying coinsurance and retrofitting compared with self-insurance and retrofitting. You can determine this “breakeven” price by having Solver set the D28 target cell (which is expected utility for coinsurance with retrofitting) equal to a value of 703.8730 (which is the expected utility of self-insurance and retrofitting) by changing cell D12, which is the premium charged for the coinsurance. Once you have the “breakeven” price, all you have to do to get the homeowner to buy the coinsurance contract is cut its price slightly below that level so that the alternative of coinsurance plus retrofitting is greater than the expected utility of retrofitting only. The insurer’s profit then is simply the difference between the price that motivates the purchase of insurance less the expected claims cost to the insurer (which is $1,250).

Q&A about Problem Set 5 with Fin4335 Student

Email from Fin4335 Student:

I just had a question about the problem set if you have the time. For part e, how are we supposed to know what the premium loading factor is? Because in the spreadsheet example that was used in the calculations but i don’t see how you are supposed to find that number in the problem set.

Email from Dr. Garven back to Fin4335 Student:

The price of insurance (AKA the “insurance premium”) is P = E(I)(1 + \lambda ), where E(I) corresponds to the expected value of the indemnity, and \lambda corresponds to the premium loading factor. When \lambda = 0, then P = E(I); i.e., insurance is actuarially fair.  As I pointed out during class last Thursday, \lambda > 0 in most private insurance market settings; i.e., insurance is typically actuarially unfair because firms incur transaction costs in forming and managing risk pools.  It follows (from the insurance pricing equation given above) that \lambda = P/E(I) - 1; i.e., the premium loading factor represents the percentage markup over and above the actuarially fair premium.

The first step in solving Part E (as noted in today’s Problem Set 5 Helpful Hint) requires determining the state-contingent indemnity schedules ({I_s}) for the four risk management strategies (i.e., self-insurance, full insurance, deductible insurance, and coinsurance).  These indemnity schedules represent the contractually agreed upon payments made by the insurer to the consumer under each contract in each of the three loss states.  Once you’ve figured out the state-contingent indemnities for each policy type, then calculate the expected values for each indemnity schedule (i.e., E(I) = \sum\limits_{s = 1}^3 {{p_s}{I_s}}). Since the insurance prices (premiums) are $3,125 for Policy A and $2,500 for both Policy B and Policy C, then finding the premium loading factor for each policy is straightforward.

 

Part E of Problem Set 5 Helpful Hint

The logic required for solving part E of Problem Set 5 is virtually identical to the logic behind the Coinsurance, Deductibles, and Upper Limits Spreadsheet spreadsheet (shown in class last Thursday); i.e., you need to determine: 1) the indemnity schedules under four alternative risk management strategies (i.e., self-insurance, full insurance, deductible insurance, and coinsurance), 2) state-contingent wealth associated with these strategies, and 3) state-contingent utilities and expected utility for these strategies.

Preparing for the first midterm in Finance 4335: Review Session (9/26) and Exam (10/1)

On September 26 and October 1, we’ll focus our attention on the first midterm exam in Finance 4335. Class on Thursday, September 26 will be devoted to a review session for the exam, and the exam will be administered during class on Tuesday, October 1.

Even though I list it as an “optional” reading, I highly recommend that y’all read my teaching note due on 9/26 entitled “Finance 4335 course synopsis for Midterm Exam 1”. In order to properly prepare for next Thursday’s review session, I also recommend reviewing the various class problems along with problem sets 2 – 4 (actually, problem set 4 is due on Thursday!) and midterm 1 from Spring 2019; solutions for class problems and problem sets in FIN 4335 are available at http://risk.garven.com/category/problem-set-solutions. After class next Thursday, I will post the solutions for problem set 4 and for midterm 1 from Spring 2019 so that everyone will the opportunity to check their work on these assignments.

Hints for solving problem set #4 (Hint #2)

A student asked me whether it is possible for the value of \alpha in problem set 4 to be negative. Here, \alpha represents the optimal level of exposure to the risky asset; 1-\alpha represents the optimal level of exposure to the safe bond. While it is certainly theoretically possible for \alpha to have a negative value, for this particular problem it turns out that \alpha > 0. The reason \alpha is positive in this case is that the 60/40 probabilities imply a positive expected return on the risky asset which exceeds the expected return on the bond. Thus, even though the stock is risky, a square root utility investor is willing to invest some of her money in the stock because, in an expected utility sense, some positive exposure to risk is worthwhile.

If you obtain a negative value for \alpha, this means that you must have made a math error somewhere. In the case of investor A, E(U(W)) = .6(105 + 25\alpha ).5 + .4(105 – 35\alpha ).5, then one can find the optimal value for investor A’s \alpha by applying the chain rule individually to both the .6(105 + 25\alpha ).5 and the .4(105 – 35\alpha ).5 terms, setting the resulting equation equal to zero (this is the so-called “first order condition”) and solving for \alpha .  Obviously the same logic applies to solving investor B’s problem; the only difference is that E(U(W)) = .6ln(105 + 25\alpha ) + .4ln(105 – 35\alpha ) for investor B.

This raises an interesting question; specifically, what would have to be different about this problem in order to obtain a negative value for \alpha?  If this problem had been originally parameterized such that the expected return on the stock was less than the expected return on the bond, this would guarantee a negative value for \alpha. For example, suppose that everything stayed the same, but that the state probabilities for the stock were 55/45 rather than 60/40. Note that with 55/45 state probabilities, the stock has an expected return of .55(.3) + .45 (-.3) = 3%, which is less than the guaranteed 5% return on the bond.  Under this scenario,  investor A’s optimal \alpha is -48.33%, which implies that she would optimally sell short $48.33 of stock and invest her initial wealth of $100 plus the $48.33 in proceeds from the short sale in the bond. From date 0 to date 1, she would earn 5% or $7.42 on her $148.33 bond investment. At date 1, she would close out her short position by buying the stock back at either $48.33 x (1.30) = $62.83 (in which case she would lose $7.08 on her $100 net investment) or at $48.33 x (.7) = $33.83 (in which case she would gain $21.92 on her $100 net investment). Thus the expected return on her portfolio is .55(-7.08%) + .45(21.92%) = 5.97%, and the standard deviation is 14.43% (short selling is risky because you might get stuck having to close out the short position at a high price; this is why the standard deviation is so high).  On the other hand, investor B’s optimal \alpha is -24% when the state probabilities for the stock are 55/45 rather than 60/40; I will leave it as an exercise for the reader to determine the expected return and risk for investor B’s optimal portfolio under this alternative scenario.

As I noted in my previous Problem Set #4 hint, if you get stuck on the math at all, you might consider inputting the data into an Excel spreadsheet and use Solver to find the optimal value for \alpha.  If you do this, be sure to email your spreadsheet model to fin4335@gmail.com sometime prior to the beginning of next Thursday’s class meeting, at which time I’ll also collect your completed problem sets.

Hints for solving problem set #4

Problem set #4 (which is due on Thursday, September 26) consists of two problems: 1) an optimal (expected utility-maximizing) portfolio problem, and 2) a stochastic dominance problem.  We’ll discuss stochastic dominance next Tuesday, but in the meantime allow me to provide you with some hints for setting up the first problem.

The first problem involves determining how to (optimally) allocate initial wealth W0 = $100 to (risky) stock and (safe) bond investments for two investors who are identical in all respects except utility. Let \alpha represent the allocation to stock; then the plan is to invest $100\alpha in the stock and $100(1-\alpha) in the bond. The key here is to find the value for \alpha which maximizes expected utility. The problem is based on the following facts:

  • U(W) = W.5; for Investor A and U(W) = ln W for Investor B;
  • W0 = $100 for both investors;
  • Current bond and stock prices are B0 and S0 respectively;
  • End-of-period bond price is B1 = B0(1.05) with probability 1.0; and
  • End-of-period stock price is S1 = S0(1.3) with probability .6 and S1 = S0(.7) with probability .4.

In order to compute expected utility of wealth for either investor, you must first determine state-contingent wealth (Ws). Since there is a 60% chance that the stock increases in value by 30%, a 40% chance that the stock decreases 30%, and a 100% chance that the bond increases in value by 5%, this implies the following:

  • 60% of the time, Ws = \alphaW0(1.3) + (1-\alpha)W0(1.05) = \alpha100(1.30) + (1-\alpha)100(1.05) = \alpha130 + (1-\alpha)105 = 105 + 25\alpha.
  • 40% of the time, Ws = \alphaW0(.7) + (1-\alpha)W0(1.05) = \alpha100(.7) + (1-\alpha)100(1.05) = \alpha70 + (1-\alpha)105 = 105 – 35\alpha.

Therefore, expected utility for Investor A is: E(U(W)) = .6(105 + 25\alpha).5 + .4(105 – 35\alpha).5, and expected utility for Investor B is E(U(W)) = .6ln (105 + 25\alpha) + .4ln(105 – 35\alpha). It is up to you to solve for the optimal value of \alpha for each investor.  There are two ways to do this – via calculus or a spreadsheet model.  Actually, I would encourage y’all to work this problem both ways because doing so will help you develop an even better grasp of the underlying principles and concepts in Finance 4335.  However, at your option, you may rely solely on building your own spreadsheet model.  If you do this, in order to receive full credit, you need to email your spreadsheet model to fin4335@gmail.com along with turning in the completed problem set.